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MODEd,,,I) · <br /> <br />Modern <br /> <br />C = 10() <br /> CM A <br /> <br />EL= ':_:). 50 ft) <br /> <br />~ LI 1 I< <br />.... A 43. () PT '79. 1 () 1 '7 <br /> '1. 027. :3 = 11,5. EJ() ( 7'~J. 10) '"'. 5 F 1. 2. 'iii PE 0.00 <br /> 1, 7 '1027. :3 8.07 1E '1" ~,5::5 ,, 'ii~ (). ()'1, :;;i',tTiltii~ PF () ,, <br /> <br />'l"oI] ,::,f <br /> <br />Under ground <br /> <br /> 5')').0 gpm = Hose F .... ' PE <br /> <br /> F 34. () PE (). ()0 <br /> <br />~. t p p '[ 3' J I:: t <br /> <br /> [..'. = 1 O0 <br /> T.::,p ,:,f Ri~e;r <br />EL= 10.0c~ ft,) <br /> <br />,~,,~. C' :[ 20 ,~.~, <br />El,..:= 6.C)0 ft) <br /> <br /> B.O.R. <br /> <br /> C ;-" '1.40 <br /> B.O.R. <br /> <br />Avai. lable 'fi. ow ~t 'i) B.'7'7 psi is 18q. 5. 1 gpm wh:Lcl", .i. <br /> <br /> ' ¢ = ' i.,~,,,,,?.,:,gpm <br />Supply pi es_,_t~ e ava±].able with '"'"?' .... , ....... <br /> <br />thus system requirement ,is ;!.0~6'~ ~:)~.'~, below !i~,,,q:~p:l.y curve. (9.8%) <br /> <br /> <br />