Laserfiche WebLink
THE ROOF LENGTH FROM CENTER OF EAVE <br />PURLIN L= <br /> <br />C=29,000,000x<~0165 <br /> <br /> [2~(l+.3)xl.2+2543/(L~.0165 <br /> <br />GIRT TO CENTER <br /> <br />OF RIDGE <br /> <br />Ch=C~(COS A)^2 <br /> <br />DETERMINE THE RELATIVE STIFFNESS OF FRAME TO ROOF <br />k/Ch-- <br /> <br />DETERMINE mD AND mS REDUCTION FACTORS FROM TABLE i AND 2 <br />BASED UPON THE STRUCTURE HAVING FRAMES. <br />mD=__ mS=__¢:,~ ~ <br /> <br />STEP 4: CALCULATE THE RESIBTANCE~ FORCE TO SIDESWAY AND SHEAR <br />FORCE IN ROOF CLADDING <br /> <br />VALUE OF CLADDING SHEAR FORCE=mS xROLLER REACTION FROM STEP <br /> <br />STEP 5:DISTRIBUTE THE SISTANCE FORCE TO SIDESWAY EQUALLY AT <br />TOP CHORD NODES OPPOSITE THE WIND LOADING ON THE WALLS <br />THE MAXIMUM COMBINE STRESSES INTERACTION VALUE = <br /> ~6~.< 1~0 THEREFORE 6X~ZS O.K. <br /> <br />STEP 6:CHECK SHEAR IN ROOFING NEAR ENDWALLS. ROOF CLADDING <br />SHEAR FORCE(STEP 4)/BUILDING WIDTH MUST BE LESS OR EQUAL TO <br />THE ADJUSTED SHEAR FROM STEP 3 ADJUSTED FOR LOAD DURATION. <br /> <br />~'~/WIDTH ~¢4) = ~'~<=llT.22PLF <br /> <br /> CHECK SHEAR TRANSFERRED TO ENDWALL DIAPHRAM. ROOF CLADDING <br /> SHEAR FORCE (STEP 4) /BUILDING WIDTH LESS DOOR OPENINGS MUST <br /> BE LESS OR EQUAL TO USEABLE SHEAR FROM STEP 3 ADJUSTED FOR <br /> ~AD DURATION (1,333) <br />Z~J~END MINUS DOOR.. 5' = ~7' .USEABLE <br /> / WIDTH USEABLE = ~? <br /> ~ <l17.22PLF <br /> <br />.-NEED ~ .~.~TO DEVELOP SHEAR IN END WALL <br /> <br /> <br />